The method withsep can be used to put a separator node between the child nodes of an Element or a Frag:

>>> from ll.xist import xsc
>>> from ll.xist.ns import html
>>> node = html.div(range(10))
>>> print(node.withsep(", ").string())
<div>0, 1, 2, 3, 4, 5, 6, 7, 8, 9</div>

The method shuffled returns a shuffled version of the Element or Frag:

>>> from ll.xist import xsc
>>> from ll.xist.ns import html
>>> node = html.div(range(10))
>>> print(node.shuffled().withsep(", ").string())
<div>8, 1, 3, 6, 7, 5, 2, 9, 4, 0</div>

The method reversed returns a reversed version of an element or fragment:

>>> from ll.xist import xsc
>>> from ll.xist.ns import html
>>> node = html.div(range(10))
>>> print(node.reversed().withsep(",").string())
<div>9,8,7,6,5,4,3,2,1,0</div>

The method mapped recursively walks the tree and generates a new tree, where all the nodes are mapped through a function. An example: To replace Python with Parrot in every text node on the Python page, do the following:

from ll.xist import xsc, parse

def p2p(node, converter):
·  if isinstance(node, xsc.Text):
·  ·  node = node.replace("Python", "Parrot")
·  ·  node = node.replace("python", "parrot")
·  return node

node = parse.tree(parse.URL("http://www.python.org"), parse.Tidy(), parse.NS(html), parse.Node(pool=xsc.Pool(xml, html)))
node = node.mapped(p2p)
node.write(open("parrot_index.html", "wb"))

The function must either return a new node, in which case this new node will be used instead of the old one, or return the old node to tell mapped that it should recursively continue with the content of the node.